The one thing that really rips heat out of my pool is rain.
So, has anyone tried flooding an autocover with ~1/4" of water? The theory being that the energy needed to evaporate all that water is much more valuable than the energy needed to simply raise the water temp. In my case:
Assumptions:
20'x45' cover (surface area)
Heat of Vaporization - 2,257 joules per gram of water
Calculations:
At 1/4" depth, I calculated 140 gallons = 530,878 grams of water
530,878 grams * 2,257 joules per gram = 1.2B joules = 1.135M BTUs
Removing 1.135M BTU's of energy in a 32,500 gallon (271,213lb water) pool is worth roughly 4.2 degrees F.
Assuming ideal conditions and no external loss/gain obviously.
So, has anyone tried flooding an autocover with ~1/4" of water? The theory being that the energy needed to evaporate all that water is much more valuable than the energy needed to simply raise the water temp. In my case:
Assumptions:
20'x45' cover (surface area)
Heat of Vaporization - 2,257 joules per gram of water
Calculations:
At 1/4" depth, I calculated 140 gallons = 530,878 grams of water
530,878 grams * 2,257 joules per gram = 1.2B joules = 1.135M BTUs
Removing 1.135M BTU's of energy in a 32,500 gallon (271,213lb water) pool is worth roughly 4.2 degrees F.
Assuming ideal conditions and no external loss/gain obviously.
