Just a question that's been bugging me...
Why is it that adding trichlor adds 0.6 ppm CYA/ppm FC, and dichlor adds 0.9 ppm CYA/ppm FC? Even though I (somehow) minored in chemistry, my chem background is more one of enthusiasm than competence
! It seems like 1 trichlor molecule (Cl3C3N3O3) would add 1 ppm CYA and 3 ppm chlorine. Likewise for dichlor, except a 2:1 ratio. Is it not a molar ratio?
Maybe just answered my own question as I was typing it :idea: . Well I guess I'll finish this just in case anyone else was wondering.
3*35.5 (atomic weight Cl) + 3*12 (aw. C) + 3*14 (aw. N) + 3*16 (aw. O) = 232.5 (trichlor molecular weight)
(3*35.5)/232.5 = 0.458 (Cl% by weight in trichlor)...... :blah: :blah:
Dang, this is more complicated than I thought! I'm stuck at this point. I've looked on this site and can't find calculations for the 0.6/0.9 ratios. Does someone (Richard? :-D ) have them?

Why is it that adding trichlor adds 0.6 ppm CYA/ppm FC, and dichlor adds 0.9 ppm CYA/ppm FC? Even though I (somehow) minored in chemistry, my chem background is more one of enthusiasm than competence



3*35.5 (atomic weight Cl) + 3*12 (aw. C) + 3*14 (aw. N) + 3*16 (aw. O) = 232.5 (trichlor molecular weight)
(3*35.5)/232.5 = 0.458 (Cl% by weight in trichlor)...... :blah: :blah:
Dang, this is more complicated than I thought! I'm stuck at this point. I've looked on this site and can't find calculations for the 0.6/0.9 ratios. Does someone (Richard? :-D ) have them?