- Thread starter Pajara
- Start date

Nobody I know pressure tests for more than a couple of days. Most likely somebody opened a valve then heard a hiss and closed it. That said, if you're concerned ask the PB to repeat the test. If he balks tell him it's in both your interest to check it now unless he's certain why it dropped and can prove it. If he doen't agree to retest then document your concern plus the situation.

I hope this helps.

Chris

We have had temps from 80 to 24 here in Tucson during this time.

Have him repeat the test for 3 days (something might have happened to the plumbing during those 3 weeks) - if it stays up you should be fine.

I'd have to disagree with this - if it leaks air, it will leak water!

P[sub]1[/sub]/T[sub]1[/sub] = P[sub]2[/sub]/T[sub]2[/sub]

P[sub]1[/sub] = 30 +14.7 =44.7 psi.

T[sub]1[/sub] = (80°f − 32) × 5/9 + 273.15 = 299.817k

T[sub]2[/sub] = (24°f − 32) × 5/9 + 273.15 = 268.706k

44.7/299.817 = P[sub]2[/sub]/268.706

P[sub]2[/sub] = 40.062.

Final gauge pressure = 40.062 - 14.7 = 25.36 psi.

(°f − 32) × 5/9 + 273.15 = k

P[SUB]1[/SUB]/T[SUB]1[/SUB] = P[SUB]2[/SUB]/T[SUB]2[/SUB]

P[SUB]1[/SUB] = 30 +14.7 =44.7 psi.

T[SUB]1[/SUB] = (80°f − 32) × 5/9 + 273.15 = 299.817k

T[SUB]2[/SUB] = (24°f − 32) × 5/9 + 273.15 = 268.706k

44.7/299.817 = P[SUB]2[/SUB]/268.706

P[SUB]2[/SUB] = 40.062.

Final gauge pressure = 40.062 - 14.7 = 25.36 psi.

P[SUB]1[/SUB]/T[SUB]1[/SUB] = P[SUB]2[/SUB]/T[SUB]2[/SUB]

P[SUB]1[/SUB] = 30 +14.7 =44.7 psi.

T[SUB]1[/SUB] = (80°f − 32) × 5/9 + 273.15 = 299.817k

T[SUB]2[/SUB] = (24°f − 32) × 5/9 + 273.15 = 268.706k

44.7/299.817 = P[SUB]2[/SUB]/268.706

P[SUB]2[/SUB] = 40.062.

Final gauge pressure = 40.062 - 14.7 = 25.36 psi.

Paj,

You can estimate the temperature impact to the pressure by using the ratio the temps in degree K. Degree K = Deg F+460.

I hope this helps.

Chris

You can estimate the temperature impact to the pressure by using the ratio the temps in degree K. Degree K = Deg F+460.

I hope this helps.

Chris

44.7/539.67 = P2/483.67.

P2 = 40.062.

For a 10 degree temperature change in Fahrenheit, you get about a 1 psi change in pressure.