CYA loss in salt water pools

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Electrons do not travel through water.

Current is carried by cations (Positively charged ions)and anions (Negatively charged ions).

The cations are attracted to the Cathode and the Anions are attracted to the Anode.

If the (+) cations do not gain electrons, they build up on the cathode and current won't flow.

If the (-) anions do not lose electrons, they build up on the anode and current won't flow.

If the electrolysis did not happen, all you would get would be a bunch of ions stuck on the anode and cathode with no current flow.

For AC, the voltage reverses course and the ions only move back and forth a tiny bit to carry the current through the water.

For AC, electrons do not flow through the water.

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Electrons do not travel through water.

Current is carried by cations (Positively charged ions)and anions (Negatively charged ions).

The cations are attracted to the Cathode and the Anions are attracted to the Anode.

If the (+) cations do not gain electrons, they build up on the cathode and current won't flow.

If the (-) anions do not lose electrons, they build up on the anode and current won't flow.

If the electrolysis did not happen, all you would get would be a bunch of ions stuck on the anode and cathode with no current flow.

For AC, the voltage reverses course and the ions only move back and forth a tiny bit to carry the current through the water.

For AC, electrons do not flow through the water.

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Are you trying to explain something?Your diagram is wrong-water molecule does not go to cathode.
 
Are you trying to explain something?Your diagram is wrong-water molecule does not go to cathode.
Where did you get this idiotic diagram?Water molecule is not an ion and does not travel to cathode.It is the Na+ that moves to cathode,gains an electron,becomes metallic sodium and reacts with water to produce hydogen gas and OH-
Same happens with Ca++ and that is how scale is formed.
 
I said that plates are HOT!
How HOT do you think the plates are getting?

What is the basis for this statement?

3 amps going through the equivalent of #2 AWG wire is not going to produce much heat.

You might get about 0.0036 watts of heat from current going through the titanium plate.
Titanium has a poor electrical conductivity, about 30 times worse than copper.

Even if you account for the resistance of the titanium vs. copper, the heat generated might be about 0.108 watts which is irrelevant with 20 GPM flowing over the plates.

All heat will transfer to the water and you won't get even a 0.1 degree temp rise for the plates.
 
Your diagram is wrong-water molecule does not go to cathode.
The cathode is surrounded by water at all times.

The water does not need to be attracted to the cathode.

All positive ions are attracted to the cathode, but only the positively charged Hydrogen ion is reduced at the cathode by receiving an electron.

All other positive ions mostly do not react.

Is the solution is acidic, you can get of lot of hydrogen ions going to the cathode.

For neutral to basic solutions, the hydrogen ions come mostly from the water molecules and hydroxide is left behind.

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It is the Na+ that moves to cathode, gains an electron, becomes metallic sodium and reacts with water to produce hydrogen gas and OH-
Sodium does not do anything in the process at all.
Same happens with Ca++ and that is how scale is formed.
Scale happens because the hydroxide raises the pH and this causes the bicarbonate to become carbonate, which combines with the calcium.

Ca2+ + OH- + HCO3- --> CaCO3 + H2O
 
I think at this point you have worn out your welcome. You clearly don’t understand chemistry at all when you make a statement like this -

It is the Na+ that moves to cathode,gains an electron,becomes metallic sodium and reacts with water to produce hydogen gas and OH-
Same happens with Ca++ and that is how scale is formed.

It is chemically impossible to reduce sodium or calcium ions in aqueous solutions using electrolysis as their half-cell potentials are so much higher than the potentials needed to split water into hydrogen and oxygen gas. You can never apply enough voltage to reduce a sodium ion back to sodium metal in aqueous solutions. Same is true with calcium.

At this point you are simply arguing to waste everyone’s time and I feel sorry for you. You could actually stay on this forum and learn a thing or two but you seem to be think you know better so I suggest you go and start your own pool forum.

You are being a troll. We don’t allow that here.
 
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If the water does not contain chloride, the primary reaction at the anode will be the production of Oxygen gas instead of chlorine gas.

The electrons flow from the negative terminal of the power source and they end up on the hydrogen atoms (Called Reduction) and the chloride or oxide atoms lose electrons (call oxidation) to become chlorine gas or hydrogen gas.

From the power source point of view, there are electrons leaving and an equal number of electrons returning, so it looks like the electrons are making a complete path, but the electrons leaving are not the same electrons as the electrons returning.

No electrons move through the water.

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