- May 13, 2012
- 73
So for my 13500 gal AGP I need 794 oz of Borax and 378 oz muriatic acid. This will bring me from 0 to 50 ppm borates. One box of Borax is 76 oz. 76/794 = 0.0957178. So multiplying my total Muriatic Acid requirement by that factors means that for every box of Borax, I must add 36.2 oz acid. My idea is to dissolve the box of Borax in a 5 gallon bucket of pool water, add the acid, and stir. This would result in a final solution that should be very close to the same pH and TA as the pool. It would also be a dose that would approximate 5 ppm Borates for my pool size. 10 of those doses would be approximately 50 ppm
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