Wrong.
Cl2 production is directly proportional to the total number of electrons (i.e. electrical current) that moves through the circuit. A "bigger" SWG simply has more electrode surface area (e.g. more plates) than a smaller one does. Consequently, the larger SWG can generate more chlorine gas per unit time, simply because the larger surface area anodes enable more chloride ions to get oxidized (i.e. they can "consume" more electrons per unit time).
Larger SWG units can produce the required chlorine amounts in shorter time than smaller units, but the amount of electrons required is the same in either case.
Stoichiometrically, SWG electrolysis generates one H2 molecule for every molecule of Cl2 that is produced. So the amount of H2 produced (i.e. the driving force of pH rise) only depends on how much chlorine is generated...not how big the SWG is.
Does it? I would think that the same amount of FC added to the pool (big vs small cell), would generate the same amount of hydrogen bubbles given the required reaction balance. A larger cell has more area to generate not only more chlorine but also more hydrogen per minute. It should be directly proportional to production rate which in turn is directly proportional to the cell area. So I don't think it should make a difference.
Thank you, I didn't think I had lost my mind.
Well you guys have certainly been busy...sorry, I was away most of the day and driving so I could not respond. Here's my thinking -
Let me first say that I do not disagree with any of you on the chemistry. For every mole of chlorine gas produced, a mole of hydrogen gas will be produced. So I'm not arguing that there is more or less hydrogen produced, it's the same for the same amount of chlorine (maybe my original post was not clear on that point). Aeration is a
physical process, the chemistry of it comes later. As a
physical process, the amount of aeration that occurs depends on the geometry of the setup, the flow rates of water and the amount of contact time that the source of aeration has with the water.
An IC-40 produces 1.4lbs of chlorine per day or 0.91667 oz/hour
An IC-60 produces 2.0lbs of chlorine per day or 1.33333 oz/hour
Let say you need to raise the FC by 4ppm in a 15,000 gallon swimming pool - that will take 8oz of chlorine gas. The IC40 requires 8.7 hours of run time at 100% output while the IC60 require 6 hours of run time at 100%. Assuming both plumbing systems are the same and your pool operates at a flow rate of 60GPM (not an unreasonable flow rate but it doesn't really matter as you could use 20GPM if you like), then the IC40 cell will have
60GPM x 8.7 hrs x 60 mins/hr = 31,320 gallons of water flow through it while the cell is producing gas bubbles. By contrast, an IC60 will have
60GPM x 6 hrs x 60 mins/hr = 21,600 gallons of water flow through it.
Unfortunately, aeration processes are not easily quantified but I doubt you can make the argument that there is a one-to-one correlation between the number of hydrogen gas molecules created and the number of CO2 molecules outgassed. Because of this, I'm inclined to conjecture that if you are flowing 31% more water through the IC40 cell while it is running, then you are agitating and expelling more CO2 gas from the pool water that uses a smaller cell than one that uses a larger cell.