Replace motor or pump?

lmigoni

Member
May 10, 2016
17
Oro Valley, Arizona
It looks like my pool pump motor has finally died forever. I want to see if it's possible and will save money to just replace the motor with a 2 speed motor or if I am better off just replacing the entire pump.

The 2-speed pool pump motors run for about $350.00 while the entire pump runs for about $475. I am not sure if it's worth saving the $175 and replacing just the motor.

This is the motor in question.
SQ1152
https://www.amazon.com/Smith-SQ1152-Service-Capacitor-Enclosure/dp/B007ATO26W
 

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madwil

Well-known member
May 2, 2011
370
lebanon tn
It's pretty simple to replace just the motor. No reason to replace pump unless it's really old or if it's losing capacity or making noise
 

lmigoni

Member
May 10, 2016
17
Oro Valley, Arizona
I forgot to give a background of what happened.

1. Summer of 2016. Pool motor would make a humming sound and would not start. I replaced the start capacitor and pool pump worked fine until now.
2. February 2017. Pool pump would start for about 3 seconds and then shut off.
3. Replaced bearings and seals. No change
4. Replaced run capacitor. No change
5. Next steps, replace motor or pump

I would like to use a 2-speed motor/pump, but can't decide what will be the best option.

Dropbox - IMG_3818.JPG

If I do replace the pool pump, this is the best option that I found but please let me know what you think and any suggestions on what other pool pumps would be good.

https://www.amazon.com/Pentair-340042-Performance-Efficient-Horsepower/dp/B002FQIYBY/ref=sr_1_1?s=lawn-garden&ie=UTF8&qid=1488907916&sr=1-1&keywords=Pentair+340042
 

lmigoni

Member
May 10, 2016
17
Oro Valley, Arizona
I agree, replacing just the motor is pretty simple. I have already removed and installed the current motor twice.
My question is if it's better to just replace the motor with an equivalent motor or would prefer a 2-speed motor. Knowing that the pool pump is 13 years old, it may be just better to replace the whole thing and start fresh.