A dilution question. (That indirectly relates to pool turnover math, I suppose..http://ppoa.org/?page_id=463)
Given: A standard I.V. tube (4mm internal diameter, with drip chamber, 60" length) containing 20ml of water, to the midline of the drip chamber. (Volume A.) Tubing oriented vertically. Infuse a second, 20ml volume of water (Volume B), allowing drainage from the bottom of the tube. Clamp tube upon completion of infusion, such that the 20ml volume contained in the tube is unchanged.
Question: What percentage of volume A remains in the tube? And if any remains, what amount would volume B have to be to completely eliminate volume A from the tubing? (A colleague and I are having a debate...)
Thanks for your help...